Incredible as it may seem, poverty lines in the United States vary dramatically from state to state. It is true that the Union as a country is one of the 10 richest countries in the world.
However, there are many cities that lead this unfortunate reverse section at the national level. Here we tell you which are the poorest cities in America.
To establish a mathematical comparison on the subject, you should know that last year’s census showed that 37 million people lived in poverty. This figure is 11.2% of the general population of the country.
The median income of an American household, according to the Census, adds up to $64,994.00 USD per year. However, those numbers are unattainable for the thousands of residents of that northern nation.
The site 247WallSt did an analysis on this topic. It was based on family income in communities with populations of 1,000 to 25,000 people.
America’s poorest cities
We start with the Mariana in Arkansas. It has a population of 3,472 inhabitants and a poverty rate of 40.0%. The median family income there is $16,704.00 USD.
Now we look at Fort Thompson, South Dakota. It has a population of only 1,275 inhabitants and a poverty rate of 48.3%. Annual income reaches up to $16,563.00 USD.
Prairie View, Texas has only 6,813 residents. It has a high poverty rate, 54.7%. Their families earn only $16,363.00 USD.
About 3,286 people live in Livingston, Alabama. It has a poverty rate of 47.3% and households receive an average of $16,233.00 USD annually.
Barely 1,834 residents return to the streets of Sibeque, Arizona. It has a very high poverty rate, 67.8%. Only $16,058.00 USD per year enters their homes.
Other cities with populations between 1,000 and 2,000 residents with high poverty rates are Jonesville, Virginia, and Scotland Neck, North Carolina.
In the same case are Rosedale, Mississippi; Waldoboro, Maine and Urania, Louisiana.